Gujarati
Hindi
4-1.Newton's Laws of Motion
medium

Find the acceleration of $3 kg$ mass when acceleration of $2 kg$ mass is $2 ms^{^{-2}}$ as shown in figure. ......... $ms^{-2}$

A

$3 $

B

$2$

C

$0.5$

D

$0$

Solution

$10-T=f_{n e t}=m_{1} a$

$\Rightarrow 10-T=2 \times 2$

$T=6$

$T=f_{\text {net }}$

$\Rightarrow T=m_{2} a$

$\Rightarrow 6=3 \times a \Rightarrow a=2 m / s^{-2}$

Standard 11
Physics

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