Acceleration of block B

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4-1.Newton's Laws of Motion

medium

Find the acceleration of block $B$

A$0$

B$\frac{5}{2}\,m/s^2$

C$\frac{5}{7}\,m/s^2$

D$\frac{5}{14}\,m/s^2$

Solution

$A: 5 g-T=5(2 a)$
$B: 2 T-8 g=8(a)$
Where $'a'$ is acceleration of block $B$ upwards
$\Rightarrow 2 g=28(a)$
$a=\frac{20}{28}=\frac{5}{7} \mathrm{m} / \mathrm{s}^{2}$

Standard 11

Physics

In the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible. The Block of mass $m_1$ will remain at rest, if

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The boxes of masses $2\, {kg}$ and $8\, {kg}$ are connected by a massless string passing over smooth pulleys. Calculate the time taken by box of mass $8\; {kg}$ to strike the ground starting from rest. (use $\left.{g}=10\, {m} / {s}^{2}\right)$ (in ${s}$)

hard

(JEE MAIN-2021)

Three blocks $A, B$ and $C$ are suspended as shown in the figure. Mass of each blocks $A$ and $C$ is $m$. If system is in equilibrium and mass of $B$ is $M$, then :

medium

The velocities of $A$ and $B$ are marked in the figure. The velocity of block $C$ is ……… $m/s$ (assume that the pulleys are ideal and string inextensible)

normal

In the given figure acceleration of wedge $'A'$ is $10\ m/s^2$ along the inclined plane. (There is no friction between $A$ $\&$ $B$ and $A$ $\&$ fixed inclined plane.) Then acceleration of block $'B'$ will ………… $m/s^2$

hard

Find the acceleration of block $B$

Solution

Similar Questions

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