Resultant of three vectors overrightarrow {OA} ,,overrightarrow {OB} and overrightarrow {OC} shown i

English

Gujarati

Hindi

3-1.Vectors

hard

Find the resultant of three vectors $\overrightarrow {OA} ,\,\overrightarrow {OB} $ and $\overrightarrow {OC} $ shown in the following figure. Radius of the circle is $R$.

A

$2R$

B

$R(1 + \sqrt 2 )$

C

$R\sqrt 2 $

D

$R(\sqrt 2 - 1)$

Solution

(b)${R_{{\rm{net}}}} = R + \sqrt {{R^2} + {R^2}} = R + \sqrt 2 R = R(\sqrt 2 + 1)$

Standard 11

Physics

Share

Similar Questions

$\vec{A}$ is a vector of magnitude $2.7$ units due east. What is the magnitude and direction of vector $4 \vec{A}$ ?

easy

Two equal forces ($P$ each) act at a point inclined to each other at an angle of $120^°$. The magnitude of their resultant is

medium

If $\overrightarrow A = 4\hat i – 3\hat j$ and $\overrightarrow B = 6\hat i + 8\hat j$ then magnitude and direction of $\overrightarrow A \, + \overrightarrow B $ will be

medium

The unit vector parallel to the resultant of the vectors $\vec A = 4\hat i + 3\hat j + 6\hat k$ and $\vec B = – \hat i + 3\hat j – 8\hat k$ is

medium

The resultant of two vectors at an angle $150^{\circ}$ is $10$ units and is perpendicular to one vector. The magnitude of the smaller vector is ……. units

hard