Two equal forces ( P each) act at a point inclined to each other at an angle of 120^° . magnitud

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3-1.Vectors

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Two equal forces ($P$ each) act at a point inclined to each other at an angle of $120^°$. The magnitude of their resultant is

A

$P/2$

B

$P/4$

C

$P$

D

$2P$

Solution

(c) $R = \sqrt {{A^2} + {B^2} + 2AB\cos \theta } $

If $A = B = P$ and $\theta = 120^\circ $ then $R = P$

Standard 11

Physics

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