Find the union of each of the following pairs of sets :
$A = \{ x:x$ is a natural number and $1\, < \,x\, \le \,6\} $
$B = \{ x:x$ is a natural number and $6\, < \,x\, < \,10\} $
$A = \{ x:x$ is a natural number and $1\, < \,x\, \le \,6\} = \{ 2,3,4,5,6\} $
$B = \{ x:x$ is a natural number and $6\, < \,x\, < \,10\} = \{ 7,8,9\} $
$A \cup B=\{2,3,4,5,6,7,8,9\}$
$\therefore A \cup B = \{ x:x \in N$ and $1\, < \,x\, < \,10\} $
If $A, B$ and $C$ are three sets such that $A \cap B = A \cap C$ and $A \cup B = A \cup C$ then
Find sets $A, B$ and $C$ such that $A \cap B, B \cap C$ and $A \cap C$ are non-empty sets and $A \cap B \cap C=\varnothing$
If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find
$A \cap C$
If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$. Then the number of elements in $A \cap B$ is equal to
Using that for any sets $\mathrm{A}$ and $\mathrm{B},$
$A \cap(A \cup B)=A$