If $A$ and $B$ are disjoint, then $n(A \cup B)$ is equal to
If $A$ and $B$ are disjoint, then $n(A \cup B)$ is equal to
- A
$n(A)$
- B
$n(B)$
- C
$n(A) + n(B)$
- D
$n(A)\,.\,n(B)$
Similar Questions
Show that $A \cap B=A \cap C$ need not imply $B = C$
Show that $A \cap B=A \cap C$ need not imply $B = C$
Show that $A \cup B=A \cap B$ implies $A=B$.
Show that $A \cup B=A \cap B$ implies $A=B$.
If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {e^x},\,x \in R\} $; $B = \{ (x,\,y):y = x,\,x \in R\} ,$ then
If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {e^x},\,x \in R\} $; $B = \{ (x,\,y):y = x,\,x \in R\} ,$ then
If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find
$B \cap D$
If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find
$B \cap D$
If $A$ and $B$ are two sets such that $A \subset B$, then what is $A \cup B ?$
If $A$ and $B$ are two sets such that $A \subset B$, then what is $A \cup B ?$