Gujarati
3-2.Motion in Plane
medium

एक प्रक्षेप्य के लिए, अधिकतम ऊँचाई एवं उड्डयन काल के वर्ग का अनुपात है ($g = 10 ms^{-2}$)

A

$5:4$

B

$5:2$

C

$5:1$

D

$10:1$

Solution

$H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}}$ तथा $T = \frac{{2u\sin \theta }}{g}$

इसलिये $\frac{H}{{{T^2}}} = \frac{{{u^2}{{\sin }^2}\theta /2g}}{{4{u^2}{{\sin }^2}\theta /{g^2}}} = \frac{g}{8} = \frac{5}{4}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.