13.Nuclei
hard

રેડિયો એકિટવ તત્ત્વ $\alpha$ અને $\beta$ કણોનું ઉત્સર્જન કરે છે,તેનો સરેરાશ જીવનકાળ $1620$ અને $405$ વર્ષ છે,તો કેટલા .......... વર્ષ પછી એકિટીવીટી $1/4$ ભાગની થાય?

A

$1500$ 

B

$300 $ 

C

$449$ 

D

$810$ 

Solution

(c) ${\lambda _\alpha } = \frac{1}{{1620}}$ per year and ${\lambda _\beta } = \frac{1}{{405}}$ per year and it is given that the fraction of the remained activity $\frac{A}{{{A_0}}} = \frac{1}{4}$

Total decay constant

$\lambda = {\lambda _\alpha } + {\lambda _\beta } = \frac{1}{{1620}} + \frac{1}{{405}} = \frac{1}{{324}}per\,year$

We know that $A = {A_0}{e^{ – \lambda t}}$==> $t = \frac{1}{\lambda }{\log _e}\frac{{{A_0}}}{A}$

==>$t = \frac{1}{\lambda }{\log _e}4 = \frac{2}{\lambda }{\log _e}2$

$=324 × 2 × 0.693 = 449 \,years.$

Standard 12
Physics

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