Intensity of electric field required to keep a water drop of radius {10^{

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1. Electric Charges and Fields

medium

The intensity of the electric field required to keep a water drop of radius ${10^{ - 5}}\, cm$ just suspended in air when charged with one electron is approximately

$260\,volt/cm$

$260\,newton/coulomb$

$130\,volt/cm$

$130\,newton/coulomb$

Solution

(b) For balance $mg = eE$ $==>$ $E = \frac{{mg}}{e}$
Also $m = \frac{4}{3}\pi \,{r^3}d = \frac{4}{3} \times \frac{{22}}{7} \times {({10^{ – 7}})^3} \times 1000\,kg$
$==>$ $E = \frac{{4/3 \times 22/7 \times {{({{10}^{ – 7}})}^3} \times 1000 \times 10}}{{1.6 \times {{10}^{ – 19}}}}$= $260\, N/C$

Standard 12

Physics

The unit of intensity of electric field is

easy

A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be…….$N/C$ $(g = 10\,m{s^{ – 1}})$

medium

Equal charges $q$ are placed at the vertices $A$ and $B$ of an equilateral triangle $ABC$ of side $a$. The magnitude of electric field at the point $C$ is

medium

What is the magnitude of a point charge due to which the electric field $30\,cm$ away has the magnitude $2\,newton/coulomb$ $[1/4\pi {\varepsilon _0} = 9 \times {10^9}\,N{m^2}/{C^2}]$

easy

A half ring of radius $R$ has a charge of $\lambda$ per unit length. The electric force on $1\, C$ charged placed at the centre is

hard

(AIIMS-2018)

The intensity of the electric field required to keep a water drop of radius ${10^{ - 5}}\, cm$ just suspended in air when charged with one electron is approximately

Solution

Similar Questions

The unit of intensity of electric field is

A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be…….$N/C$ $(g = 10\,m{s^{ – 1}})$

Equal charges $q$ are placed at the vertices $A$ and $B$ of an equilateral triangle $ABC$ of side $a$. The magnitude of electric field at the point $C$ is

What is the magnitude of a point charge due to which the electric field $30\,cm$ away has the magnitude $2\,newton/coulomb$ $[1/4\pi {\varepsilon _0} = 9 \times {10^9}\,N{m^2}/{C^2}]$

A half ring of radius $R$ has a charge of $\lambda$ per unit length. The electric force on $1\, C$ charged placed at the centre is

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