For the reaction : $2A + B \to A_2B$ ; the rate $= K[A]\, [B]^2$ with $K = 2.0\times10^{-6}\, lit^2\, mol^{-2}\, sec^{-1}$. Initial concentration of $A$ and $B$ are $0.2\, mol/lit$ and $0.4\, mol/lit$ respectively. Calculate the rate of reaction after $[A]$ is reduced to $0.12\, mol/litre$.
$3.11\times10^{-8}$
$8.6\times10^{-8}$
$5.21\times10^{-6}$
None of these
The mechanism of the reaction $A + 2B \to D$ is
$2B\xrightarrow{k}{B_2}$ [Slow]
${B_2} + A \to D$ [Fast]
The rate law expression, order with respect to $A$, order with respect to $'B'$ and overall order are respectively
For the reaction $A + 2B \to C,$ rate is given by $R$ $ = [A]{[B]^2}$ then the order of the reaction is
For reaction $2A + B \to $ products, the active mass of $ B $ is kept constant and that of $A$ is doubled. The rate of reaction will then
A study of chemical kinetics of the reaction $A + B \to$ Products, gave the following data at $25\,^oC$.
Exp. No. | [A] | [B] | Rate |
$1.$ | $1.0$ | $0.15$ | $4.2 × 10^{-6}$ |
$2.$ | $2.0$ | $0.15$ | $8.4 × 10^{-6}$ |
$3.$ | $1.0$ | $0.20$ | $5.6 × 10^{-6}$ |
Find out rate law
For a chemical reaction $A + B \rightarrow$ Product, the order is $1$ with respect to $A$ and $B$.
Rate $mol\,L^{-1}\,s^{-1}$ | $[A]$ $mol\,L^{-1}$ | $[B]$ $mol\,L^{-1}$ |
$0.10$ | $20$ | $0.5$ |
$0.40$ | $x$ | $0.5$ |
$0.80$ | $40$ | $y$ |
What is the value of $x$ and $y ?$