For the statements $p$ and $q$, consider the following compound statements :
$(a)$ $(\sim q \wedge( p \rightarrow q )) \rightarrow \sim p$
$(b)$ $((p \vee q) \wedge \sim p) \rightarrow q$
Then which of the following statements is correct?
$(a)$ and $(b)$ both are not tautologies.
$(a)$ and $(b)$ both are tautologies.
$(a)$ is a tautology but not $(b).$
$(b)$ is a tautology but not $(a).$
The proposition $\left( { \sim p} \right) \vee \left( {p\, \wedge \sim q} \right)$
Negation of "If India wins the match then India will reach in the final" is :-
Consider the following two statements :
$P :$ lf $7$ is an odd number, then $7$ is divisible by $2.$
$Q :$ If $7$ is a prime number, then $7$ is an odd number.
lf $V_1$ is the truth value of the contrapositive of $P$ and $V_2$ is the truth value of contrapositive of $Q,$ then the ordered pair $(V_1, V_2)$ equals
The contrapositive of $(p \vee q) \Rightarrow r$ is
The Statement that is $TRUE$ among the following is