Force between two identical bar magnets whose | vedclass

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Question

(d)In magnetic dipole, force $ \propto \frac{1}{{{r^4}}}$
Hence new force $ = \frac{{4.8}}{{{2^4}}} = \frac{{4.8}}{{16}} = 0.3\;N$

Vedclass · Accepted Answer

$0.3$

Vedclass · Answer

(d)In magnetic dipole, force $ \propto \frac{1}{{{r^4}}}$
Hence new force $ = \frac{{4.8}}{{{2^4}}} = \frac{{4.8}}{{16}} = 0.3\;N$

Force between two identical bar magnets whose centres are $r $ metre apart is $ 4.8\, N$ , when their axes are in the same line. If separation is increased to $2r,$ the force between them is reduced to.....$N$