Force between two unit pole strength placed a | vedclass

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Question

(c)$F = {10^{ - 7}} 	imes \frac{{{m^2}}}{{{r^2}}} = \frac{{{{10}^{ - 7}}{{\left( 1 ight)}^2}}}{{{{\left( 1 ight)}^2}}} = {10^{ - 7}}\,N$

Vedclass · Accepted Answer

${10^{ - 7\,}}\,N$

Vedclass · Answer

(c)$F = {10^{ - 7}} 	imes \frac{{{m^2}}}{{{r^2}}} = \frac{{{{10}^{ - 7}}{{\left( 1 ight)}^2}}}{{{{\left( 1 ight)}^2}}} = {10^{ - 7}}\,N$

Force between two unit pole strength placed at a distance of one metre is