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5.Magnetism and Matter
easy
Force between two unit pole strength placed at a distance of one metre is
A
$1 \,N$
B
$\frac{{{{10}^{ - 7}}}}{{4\pi }}\,N$
C
${10^{ - 7\,}}\,N$
D
$4\pi \times {10^{ - 7}}\,N$
Solution
(c)$F = {10^{ – 7}} \times \frac{{{m^2}}}{{{r^2}}} = \frac{{{{10}^{ – 7}}{{\left( 1 \right)}^2}}}{{{{\left( 1 \right)}^2}}} = {10^{ – 7}}\,N$
Standard 12
Physics
