Four particles A, B, C and D of equal mass are placed at four corners of a square. They m

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5.Work, Energy, Power and Collision

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Four particles $A, B, C$ and $D$ of equal mass are placed at four corners of a square. They move with equal uniform speed $v$ towards the intersection of the diagonals. After collision, $A$ comes to rest, $B$ traces its path back with same speed and $C$ and $D$ move with equal speeds. What is the velocity of $C$ after collision

A

$\frac{2v}{3}$

B

$2\,v$

C

$\frac{v}{2}$

D

$v$

Solution

Total initial momentum $=0$

So final total mementum must be zero.

So best possible answer is $(3)$

$\mathrm{C}$ and $\mathrm{D}$ will move opposite to $\mathrm{B}$.

Standard 11

Physics

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