- Home
- Standard 11
- Physics
5.Work, Energy, Power and Collision
normal
Four particles $A, B, C$ and $D$ of equal mass are placed at four corners of a square. They move with equal uniform speed $v$ towards the intersection of the diagonals. After collision, $A$ comes to rest, $B$ traces its path back with same speed and $C$ and $D$ move with equal speeds. What is the velocity of $C$ after collision
A
$\frac{2v}{3}$
B
$2\,v$
C
$\frac{v}{2}$
D
$v$
Solution
Total initial momentum $=0$
So final total mementum must be zero.
So best possible answer is $(3)$
$\mathrm{C}$ and $\mathrm{D}$ will move opposite to $\mathrm{B}$.
Standard 11
Physics
