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5.Work, Energy, Power and Collision
normal
The variation of force $F$ acting on a body moving along $x$-axis varies with its position $(x)$ as shown in figure The body is in stable equilibrium state at
A
$P$
B
$Q$
C
$R$
D
Both $P$ and $Q$
Solution
(b)
$F=\frac{-d U}{d x} \Rightarrow \frac{d F}{d x}=\frac{-d^2 U}{d x^2}$
If $\frac{d F}{d x} < 0 \Rightarrow \frac{d^2 U}{d x^2} > 0$ Point of minima and stable equilibrium at $Q \frac{d F}{d x} < 0$ (Slope of $F-x$ curve)
So $Q$ is point of stable equilibrium
Standard 11
Physics
