From eighty cards numbered 1 to 80 , two cards are selected randomly. probability that both cards ha

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14.Probability

easy

From eighty cards numbered $1$ to $80$, two cards are selected randomly. The probability that both the cards have the numbers divisible by $4$ is given by

A

$\frac{{21}}{{316}}$

B

$\frac{{19}}{{316}}$

C

$\frac{1}{4}$

D

None of these

Solution

(b) Total number of ways $ = {\,^{80}}{C_2}$

and favorable ways ${ = ^{20}}{C_2}$

$\therefore$ Required probability $P = \frac{{^{20}{C_{_2}}}}{{^{80}{C_2}}} = \frac{{19}}{{316}}$.

Standard 11

Mathematics

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