Given $z$ is a complex number such that $|z| < 2,$ then the maximum value of $|iz + 6 -8i|$ is equal to-
$10$
$8$
$12$
$6$
For any complex number $z,\bar z = \left( {\frac{1}{z}} \right)$if and only if
If the conjugate of $(x + iy)(1 - 2i)$ be $1 + i$, then
Let $z$ and $w$ be the two non-zero complex numbers such that $|z|\, = \,|w|$ and $arg\,z + arg\,w = \pi $. Then $z$ is equal to
The argument of the complex number $\sin \,\frac{{6\pi }}{5}\, + \,i\,\left( {1\, + \,\cos \,\frac{{6\pi }}{5}} \right)$ is
If the equation, $x^{2}+b x+45=0(b \in R)$ has conjugate complex roots and they satisfy $|z+1|=2 \sqrt{10},$ then