Given below are the statements about diborane.

$(a)$ Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.

$(b)$ Each boron atom is in sp $^{2}$ hybridized state.

$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.

$(d)$ Diborane is a planar molecule.

The option with correct statement(s) is :

The bond dissociation energy of $B- F$ in $BF_3$ is $646 \,kJ\, mol^{-1}$ whereas that of $C - F$ in $CF_4$ is $515\, kJ\, mol^{-1}.$ The correct reason for higher $B- F$ bond dissociation energy as compared to that of $C-F$ is

Explain physical characteristic of group $13$ elements. 

The incorrect stability order of $+3$ and $+1$ states of $13^{th}$ group elements (boron family) is

In diborane, the two $H - B - H$ angles are nearly

The reaction of $\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3} \mathrm{Cl}_{3}$ $(A)$ with $\mathrm{LiBH}_{4}$ in tetrahydrofurane gives inorganic benzene $(B)$. Further, the reaction of $(A)$ with $(C)$ leads to $\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3}(\mathrm{Me})_{3}$. than Compounds $(\mathrm{B})$ and $(\mathrm{C})$ respectively, are