Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$ : Product of Pressure $(P)$ and time $(t)$ has the same dimension as that of coefficient of viscosity.
Reason $R$ : Coefficient of viscosity $=\frac{\text { Force }}{\text { Velocity gradient }}$
Question : Choose the correct answer from the options given below
Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$ : Product of Pressure $(P)$ and time $(t)$ has the same dimension as that of coefficient of viscosity.
Reason $R$ : Coefficient of viscosity $=\frac{\text { Force }}{\text { Velocity gradient }}$
Question : Choose the correct answer from the options given below
- [JEE MAIN 2022]
- A
Both $A$ and $R$ true, and $R$ is correct explanation of $A$
- B
Both $A$ and $R$ are true but $R$ is $NOT$ the correct explanation of $A$.
- C
$A$ is true but $R$ is false.
- D
$A$ is false but $R$ is true.
Similar Questions
Number of particles is given by $n = - D\frac{{{n_2} - {n_1}}}{{{x_2} - {x_1}}}$ crossing a unit area perpendicular to X-axis in unit time, where ${n_1}$ and ${n_2}$ are number of particles per unit volume for the value of $x$ meant to ${x_2}$ and ${x_1}$. Find dimensions of $D$ called as diffusion constant
Number of particles is given by $n = - D\frac{{{n_2} - {n_1}}}{{{x_2} - {x_1}}}$ crossing a unit area perpendicular to X-axis in unit time, where ${n_1}$ and ${n_2}$ are number of particles per unit volume for the value of $x$ meant to ${x_2}$ and ${x_1}$. Find dimensions of $D$ called as diffusion constant
If momentum $(P),$ area $(A)$ and time $(T)$ are taken to be the fundamental quantities then the dimensional formula for energy is :
If momentum $(P),$ area $(A)$ and time $(T)$ are taken to be the fundamental quantities then the dimensional formula for energy is :
- [JEE MAIN 2020]
Even if a physical quantity depends upon three quantities, out of which two are dimensionally same, then the formula cannot be derived by the method of dimensions. This statement
Even if a physical quantity depends upon three quantities, out of which two are dimensionally same, then the formula cannot be derived by the method of dimensions. This statement
The dimensions of ${e^2}/4\pi {\varepsilon _0}hc$, where $e,\,{\varepsilon _0},\,h$ and $c$ are electronic charge, electric permittivity, Planck’s constant and velocity of light in vacuum respectively
The dimensions of ${e^2}/4\pi {\varepsilon _0}hc$, where $e,\,{\varepsilon _0},\,h$ and $c$ are electronic charge, electric permittivity, Planck’s constant and velocity of light in vacuum respectively
Dimensions of resistance in an electrical circuit in terms of dimension of mass $M,$ of length $L$ of time $T$ and of current $I$ , would be
Dimensions of resistance in an electrical circuit in terms of dimension of mass $M,$ of length $L$ of time $T$ and of current $I$ , would be
- [AIPMT 2007]