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1.Relation and Function
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Greatest value of the function, $f(x) = - 1 + \frac{2}{{{2^x}^2 + 1}}$ is
A
$1$
B
$3/2$
C
$2/3$
D
$0$
Solution
$f(x)=-1+\frac{2}{2^{x^{2}}+1}$
Clearly $f(x)$ in an even function and $f(x)$ is greatest
when $\frac{2}{2^{x^{2}}+1}$ is greatest.
(given)
Also, $\frac{2}{2^{x^{2}}+1}$ is greatest when $2^{x^{2}}+1$ is least,
which occurs when $x=0.$
Hence greatest value is $f(0)=0.$
Standard 12
Mathematics
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