1.Relation and Function
normal

Greatest value of the function, $f(x) =  - 1 + \frac{2}{{{2^x}^2 + 1}}$ is 

A

$1$

B

$3/2$

C

$2/3$

D

$0$

Solution

$f(x)=-1+\frac{2}{2^{x^{2}}+1}$

Clearly $f(x)$ in an even function and $f(x)$ is greatest

when $\frac{2}{2^{x^{2}}+1}$ is greatest.

(given)

Also, $\frac{2}{2^{x^{2}}+1}$ is greatest when $2^{x^{2}}+1$ is least,

which occurs when $x=0.$

Hence greatest value is $f(0)=0.$

Standard 12
Mathematics

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