If cos ,x = frac{{2cos y - 1}}{{2 - cos | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Given $\cos x=\frac{2 \cos y-1}{2-\cos y}$

Applying compoundo and dividendo rule

$\frac{1+\cos x}{1-\cos x}=\frac{2 \cos y-1+2-\cos y}{2-\cos y-

Vedclass · Accepted Answer

$\sqrt 3$

Vedclass · Answer

Given $\cos x=\frac{2 \cos y-1}{2-\cos y}$

Applying compoundo and dividendo rule

$\frac{1+\cos x}{1-\cos x}=\frac{2 \cos y-1+2-\cos y}{2-\cos y-2 \cos y+1}$

$\Longrightarrow \frac{2 \cos ^{2} x / 2}{2 \sin ^{2} x / 2}=\frac{1+\cos y}{3(1-\cos y)}=\frac{\cos ^{2} y / 2}{3\left(2 \sin ^{2} y / 2ight)}$

$\Longrightarrow 	an ^{2} \frac{x}{2}=3 	an ^{2} \frac{y}{2}$

$\Longrightarrow 	an \frac{x}{2} \cot \frac{y}{2}=\sqrt{3}$

If $\cos \,x = \frac{{2\cos y - 1}}{{2 - \cos y}},x,\,y\, \in \,\left( {0,\pi } \right),$ then $tan(x/2)cot(y/2) =$

Similar Questions

The sum of solutions in $x \in (0,2\pi )$ of the equation, $4\cos (x).\cos \left( {\frac{\pi }{3} - x} \right).\cos \left( {\frac{\pi }{3} + x} \right) = 1$ is equal to

The number of solutions of the given equation $\tan \theta + \sec \theta = \sqrt 3 ,$ where $0 < \theta < 2\pi $ is

The number of values of $\alpha $ in $[0, 2\pi]$ for which $2\,{\sin ^3}\,\alpha - 7\,{\sin ^2}\,\alpha + 7\,\sin \,\alpha = 2$ , is

If $\cot \theta + \cot \left( {\frac{\pi }{4} + \theta } \right) = 2$, then the general value of $\theta $ is

Let $f(x) = sinx + 2sin^2x + 3sin^3x + 4sin^4x+....\infty $ , then number of solution $(s)$ of equation $f(x) = 2$ in $x \in \left[ { - \pi ,\pi } \right] - \left\{ { \pm \frac{\pi }{2}} \right\}$ is