If A =a₁ hat{ i }+b₁ hat{ j } and B =a₂ hat{ i }+b₂ hat{ j } , condition that they are perpe

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3-1.Vectors

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If $A =a_1 \hat{ i }+b_1 \hat{ j }$ and $B =a_2 \hat{ i }+b_2 \hat{ j }$, the condition that they are perpendicular to each other is

A$\frac{a_1}{b_1}=-\frac{b_2}{a_2}$

B$a_1 b_1=a_2 b_2$

C$\frac{a_1}{a_2}=-\frac{b_1}{b_2}$

DNone of these

Solution

(a)
Their dot product should be zero.

Standard 11

Physics

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