colum $I$ | colum $II$ |
$(A)$ $A \cdot B =| A \times B |$ | $(p)$ $\theta=90^{\circ}$ |
$(B)$ $A \cdot B = B ^2$ | $(q)$ $\theta=0^{\circ}$ or $180^{\circ}$ |
$(C)$ $|A+B|=|A-B|$ | $(r)$ $A=B$ |
$(D)$ $|A \times B|=A B$ | $(s)$ None |
The angle made by the vector $\left( {\hat i\,\, + \;\,\hat j} \right)$ with $x-$ axis and $y$ axis is
Show that the scalar product of two vectors obeys the law of commutative.