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6-2.Equilibrium-II (Ionic Equilibrium)
medium
The solubility in water of a sparingly soluble salt $A{B_2}$ is $1.0 \times {10^{ - 5}}mol\,{l^{ - 1}}$. Its solubility product number will be
A
$4 \times {10^{ - 15}}$
B
$4 \times {10^{ - 10}}$
C
$1 \times {10^{ - 15}}$
D
$1 \times {10^{ - 10}}$
(AIEEE-2003)
Solution
(a) $A{B_2} ⇌ \mathop {{A^ + }\,\,\,}\limits_{1 \times {{10}^{ – 5}}} \,\, + \,\,\,\,\,\mathop {2{B^ – }}\limits_{2 \times {{10}^{ – 5}}} $
${K_{sp}} = [1 \times {10^{ – 5}}]\,\,{[2 \times {10^{ – 5}}]^2} = 4 \times {10^{ – 15}}$
Standard 11
Chemistry
