If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find

$A \cap \left( {B \cup C} \right)$

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$A \cap(B \cup C)=(A \cap B) \cup(A \cap C)$

$=\{7,9,11\} \cup\{11\}=\{7,9,11\}$

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