If $E$ and $F$ are events such that $P ( E )=\frac{1}{4}$, $P ( F )=\frac{1}{2}$ and $P(E$ and $F )=\frac{1}{8},$ find : $P ( E$ or  $F )$

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Here, $P ( E )=\frac{1}{4}$,  $P ( F )=\frac{1}{2},$ and  $P ( E$ and $F )=\frac{1}{8}$

We know that $P ( E$ and $F )= P ( E )+ P ( F )- P ( E$ and  $F )$

$\therefore P(E $ or  $F)=\frac{1}{4}+\frac{1}{2}-\frac{1}{8}$ $=\frac{2+4-1}{8}=\frac{5}{8}$

Similar Questions

Two persons $A$ and $B$ throw a (fair)die (six-faced cube with faces numbered from $1$ to $6$ ) alternately, starting with $A$. The first person to get an outcome different from the previous one by the opponent wins. The probability that $B$ wins is

  • [KVPY 2014]

Let $A$ and $B$ be events for which $P(A) = x$, $P(B) = y,$$P(A \cap B) = z,$ then $P(\bar A \cap B)$ equals

Let $S$ be a set containing n elements and we select $2$ subsets $A$ and $B$ of $S$ at random then the probability that $A \cup B = S$ and $A \cap B = \phi $ is

Two cards are drawn at random and without replacement from a pack of $52$ playing cards. Finds the probability that both the cards are black.

Prove that if $E$ and $F$ are independent events, then so are the events $\mathrm{E}$ and $\mathrm{F}^{\prime}$.