Fill in the blanks in following table :
$P(A)$
$P(B)$
$P(A \cap B)$
$P (A \cup B)$
$\frac {1}{3}$
$\frac {1}{5}$
$\frac {1}{15}$
........
Fill in the blanks in following table :
| $P(A)$ | $P(B)$ | $P(A \cap B)$ | $P (A \cup B)$ |
| $\frac {1}{3}$ | $\frac {1}{5}$ | $\frac {1}{15}$ | ........ |
$P ( A )=\frac{1}{3}$, $P ( B )=\frac{1}{5}$, $P ( A \cap B )=\frac{1}{15}$
Here,
We know that $P ( A \cup B )= P ( A )+ P ( B )- P ( A \cap B )$
$\therefore P(A \cup B)$ $=\frac{1}{3}+\frac{1}{5}+\frac{1}{15}$ $=\frac{5+3-1}{15}$ $=\frac{7}{15}$
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