8. Introduction to Trigonometry
easy

यदि $\cos A =\frac{4}{5}$ है, तो $\tan A$ का मान है

A

$\frac{3}{4}$

B

$\frac{3}{5}$

C

$\frac{4}{3}$

D

$\frac{5}{3}$

Solution

Given, $\cos A=\frac{4}{5}$

$\therefore \quad \sin A=\sqrt{1-\cos ^{2}A}$

$=\sqrt{1-\left(\frac{4}{5}\right)^{2}}=\sqrt{1-\frac{16}{25}}=\sqrt{\frac{9}{25}}=\frac{3}{5}$

Now, $\quad \tan A=\frac{\sin A}{\cos A}=\frac{5}{4}=\frac{3}{4}$

Hence, the required value of tan $A$ is $\frac{3}{4}$

 

Standard 10
Mathematics

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