If R is the radius of earth and g is the acce | vedclass

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Question

(c)

Acceleration due to gravity at earth's surface is given by,

$g=\frac{G M}{R^2}$

$M=\frac{4}{3} \pi R^3 \rho$

$M \rightarrow$ Mass

Vedclass · Accepted Answer

$\frac{3 g}{4 \pi R G}$

Vedclass · Answer

(c)

Acceleration due to gravity at earth's surface is given by,

$g=\frac{G M}{R^2}$

$M=\frac{4}{3} \pi R^3 ho$

$M ightarrow$ Mass of earth

$ho ightarrow$ Density of earth

$R ightarrow$ Radius of earth

$\Rightarrow g=\frac{G}{R^2} 	imes \frac{4}{3} \pi R^3 ho$

$\Rightarrow ho=\frac{3 g}{4 \pi G R}$

If $R$ is the radius of earth and $g$ is the acceleration due to gravity on the earth's surface. Then mean density of earth is ..........

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