If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smal

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1.Units, Dimensions and Measurement

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If $50$ Vernier divisions are equal to $49$ main scale divisions of a travelling microscope and one smallest reading of main scale is $0.5 \mathrm{~mm}$, the Vernier constant of travelling microscope is:

A

$0.1 \mathrm{~mm}$

B

$0.1 \mathrm{~cm}$

C

$0.01 \mathrm{~cm}$

D

$0.01 \mathrm{~mm}$

(JEE MAIN-2024)

Solution

$50 \mathrm{~V}+\mathrm{S}=49 \mathrm{~S}+\mathrm{S}$

$\mathrm{S}=50(\mathrm{~S}-\mathrm{V})$

$5=50(\mathrm{~S}-\mathrm{V})$

$\mathrm{S}-\mathrm{V}=\frac{0.5}{50}=\frac{1}{100}=0.01 \mathrm{~mm}$

Standard 11

Physics

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