જો {{{x^2}} over {({x^2} + {a^2}),({x^2} + {b^2})}} = kleft( {{{{a^2}} over {{x^2} + {a^2}}}

English

Gujarati

Hindi

Basic of Logarithms

easy

જો ${{{x^2}} \over {({x^2} + {a^2})\,({x^2} + {b^2})}} = k\left( {{{{a^2}} \over {{x^2} + {a^2}}} - {{{b^2}} \over {{x^2} + {b^2}}}} \right)$ તો $k =$

${a^2} - {b^2}$

${1 \over {a + b}}$

${1 \over {a - b}}$

${1 \over {{a^2} - {b^2}}}$

(d) ${x^2} = k\,\,[{a^2}({x^2} + {b^2}) – {b^2}({x^2} + {a^2})]$

$ \Rightarrow $${x^2} = k\,[({a^2} – {b^2}){x^2}] \Rightarrow 1 = k({a^2} – {b^2})$

$\therefore k = {1 \over {{a^2} – {b^2}}}$.

Standard 11

Mathematics

medium

easy

easy

easy

easy