If z = cos frac{pi }{6} + isin frac{pi }{6} t | vedclass

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(b)$z = \cos \frac{\pi }{6} + i\sin \frac{\pi }{6} = \frac{{\sqrt 3 }}{2} + \frac{i}{2}$
$	herefore \,\,|z|\, = \sqrt {\frac{3}{4} + \frac{1}{4}} =

Vedclass · Accepted Answer

$|z|\, = 1,arg\,z = \frac{\pi }{6}$

Vedclass · Answer

(b)$z = \cos \frac{\pi }{6} + i\sin \frac{\pi }{6} = \frac{{\sqrt 3 }}{2} + \frac{i}{2}$
$	herefore \,\,|z|\, = \sqrt {\frac{3}{4} + \frac{1}{4}} = 1$
and $arg\,(z) = {	an ^{ - 1}}\,\left( {\frac{y}{x}} ight) = {	an ^{ - 1}}\left( {\frac{{1/2}}{{\sqrt 3 /2}}} ight) = {	an ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} ight)$
$ \Rightarrow \,\,arg(z)\, = {	an ^{ - 1}}\left( {	an \frac{\pi }{6}} ight) = \frac{\pi }{6}$.

If $z = \cos \frac{\pi }{6} + i\sin \frac{\pi }{6}$ then

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