If {z₁} and {z₂} are two complex numbers, then |{z₁} + {z₂}| is

English

Gujarati

Hindi

4-1.Complex numbers

normal

If ${z_1}$ and ${z_2}$ are two complex numbers, then $|{z_1} + {z_2}|$ is

A

$ \le \,|{z_1}| + |{z_2}|$

B

$ \le \,|{z_1}| - |{z_2}|$

C

$ < \,|{z_1}| + |{z_2}|$

D

$ > \,|{z_1}| + |{z_2}|$

Solution

(a)$|{z_1} + {z_2}|\, \le \,|{z_1}| + |{z_2}|$

Standard 11

Mathematics

Share

Similar Questions

Let $z\,\ne -i$ be any complex number such that $\frac{{z – i}}{{z + i}}$ is a purely imaginary number. Then $z +\frac {1}{z}$ is

hard

(JEE MAIN-2014)

Let $\quad S=\left\{z \in C-\{i, 2 i\}: \frac{z^2+8 i z-15}{z^2-3 i z-2} \in R \right\}$. $\alpha-\frac{13}{11} i \in S , \alpha \in R -\{0\}$, then $242 \alpha^2$ is equal to

normal

(JEE MAIN-2023)

The true statement is

normal

The statement $(a + ib) < (c + id)$ is true for

normal

Let $\frac{{1 – ix}}{{1 + ix}} = a – ib$ and ${a^2} + {b^2} = 1$, where $a$ and $b$ are real, then $x = $

medium