Gujarati
8. Sequences and Series
easy

If $a,\,b,\,c$ are in $A.P.$, then $(a + 2b - c)$ $(2b + c - a)$ $(c + a - b)$ equals

A

$\frac{1}{2}abc$

B

$abc$

C

$2\ abc$

D

$4\ abc$

Solution

(d) $(a + 2b – c)\,(2b + c – a)\,(c + a – b)$

$ = (a + a + c – c)(a + c + c – a)(2b – b)$ $ = 4\,abc.$

$(\because a,b,c$ are in $A.P.$,

$\therefore 2b = a + c)$.

Standard 11
Mathematics

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