Let a_1=8, a_2, a_3, ldots a_n be an A.P. If | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$a_1+a_2+a_3+a_4=50$

$\Rightarrow 32+6 d=50$

$\Rightarrow d=3$

and, $a_{n-3}+a_{n-2}+a_{n-1}+a_n=170$

$\Rightarrow 32+(4 n -10) \cdot 3=17

Vedclass · Accepted Answer

$754$

Vedclass · Answer

$a_1+a_2+a_3+a_4=50$

$\Rightarrow 32+6 d=50$

$\Rightarrow d=3$

and, $a_{n-3}+a_{n-2}+a_{n-1}+a_n=170$

$\Rightarrow 32+(4 n -10) \cdot 3=170$

$\Rightarrow n =14$

$a _7=26, a _8=29$

$\Rightarrow a _7 \cdot a _8=754$

Let $a_1=8, a_2, a_3, \ldots a_n$ be an $A.P.$ If the sum of its first four terms is $50$ and the sum of its last four terms is $170$ , then the product of its middle two terms is

Similar Questions

If $a,b,c,d,e$ are in $A.P.$ then the value of $a + b + 4c$ $ - 4d + e$ in terms of $a$, if possible is

Write the first five terms of the sequences whose $n^{t h}$ term is $a_{n}=(-1)^{n-1} 5^{n+1}$

If the ${p^{th}}$ term of an $A.P.$ be $\frac{1}{q}$ and ${q^{th}}$ term be $\frac{1}{p}$, then the sum of its $p{q^{th}}$ terms will be

Let the sum of the first $n$ terms of a non-constant $A.P., a_1, a_2, a_3, ……$ be $50\,n\, + \,\frac{{n\,(n\, - 7)}}{2}A,$ where $A$ is a constant. If $d$ is the common difference of this $A.P.,$ then the ordered pair $(d,a_{50})$ is equal to

The value of $\sum\limits_{r = 1}^n {\log \left( {\frac{{{a^r}}}{{{b^{r - 1}}}}} \right)} $ is