If a,,b,,c are in G.P., then | vedclass

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Question

(b) If $a,\;b,\;c$ are in $G.P.$ Then ${b^2} = ac$

$ \Rightarrow $ ${b^2}(a - c) = ac(a - c)$

$ \Rightarrow $${b^2}a - {b^2}c = {a^2}c - a{c^2}$

Vedclass · Accepted Answer

$a({b^2} + {c^2}) = c({a^2} + {b^2})$

Vedclass · Answer

(b) If $a,\;b,\;c$ are in $G.P.$ Then ${b^2} = ac$

$ \Rightarrow $ ${b^2}(a - c) = ac(a - c)$

$ \Rightarrow $${b^2}a - {b^2}c = {a^2}c - a{c^2}$

$ \Rightarrow $ $a({b^2} + {c^2}) = c({a^2} + {b^2})$.

Trick : Put $a = 1,\;b = 2,\;c = 4$ and check the alternates.

If $a,\,b,\,c$ are in $G.P.$, then

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