If $x$ is real, the expression $\frac{{x + 2}}{{2{x^2} + 3x + 6}}$ takes all value in the interval
If $x$ is real, the expression $\frac{{x + 2}}{{2{x^2} + 3x + 6}}$ takes all value in the interval
- [IIT 1969]
- A
$\left( {\frac{1}{{13}},\frac{1}{3}} \right)$
- B
$\left[ { - \frac{1}{{13}},\frac{1}{3}} \right]$
- C
$\left( { - \frac{1}{3},\frac{1}{{13}}} \right)$
- D
None of these
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Consider the following two statements
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$II$. There do not exist two consecutive integers, the sum of whose squares is $365$.Then,
- [KVPY 2018]
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