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4-2.Quadratic Equations and Inequations
easy
The roots of the equation $4{x^4} - 24{x^3} + 57{x^2} + 18x - 45 = 0$, If one of them is $3 + i\sqrt 6 $, are
A
$3 - i\sqrt 6 , \pm \sqrt {\frac{3}{2}} $
B
$3 - i\sqrt 6 , \pm \frac{3}{{\sqrt 2 }}$
C
$3 - i\sqrt 6 , \pm \frac{{\sqrt 3 }}{2}$
D
None of these
Solution
(c) ${x^2} – 6x + 15 = 0$is quadratic corresponding to roots $3 \pm i\sqrt 6 $ and dividing the given equation by this, we get $4{x^2} – 3 = 0$==> $x = \pm \frac{{\sqrt 3 }}{2}$.
Standard 11
Mathematics