If $x$ be real, the least value of ${x^2} - 6x + 10$ is
$1$
$2$
$3$
$10$
(a) If ${x^2} – 6x + 10 = {(x – 3)^2} + 1$ For real $x$, least value of ${(x – 3)^2} + 1$is $1$.
The number of real solutions of the equation $x\left(x^2+3|x|+5|x-1|+6|x-2|\right)=0$ is
If for a posiive integer $n$ , the quadratic equation, $x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right) + .\;.\;.\; + \left( {x + \overline {n – 1} } \right)\left( {x + n} \right) = 10n$ has two consecutive integral solutions, then $n$ is equal to:
Let $a, b$ be non-zero real numbers. Which of the following statements about the quadratic equation $a x^2+(a+b) x+b=0$ is necessarily true?
$I$. It has at least one negative root.
$II$. It has at least one positive root.
$III$. Both its roots are real.
Suppose $m, n$ are positive integers such that $6^m+2^{m+n} \cdot 3^w+2^n=332$. The value of the expression $m^2+m n+n^2$ is
If $x$ is real, then the value of $\frac{{{x^2} + 34x – 71}}{{{x^2} + 2x – 7}}$ does not lie between
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