If $^n{C_{12}} = {\,^n}{C_6}$, then $^n{C_2} = $
If $^n{C_{12}} = {\,^n}{C_6}$, then $^n{C_2} = $
- A
$72$
- B
$153$
- C
$306$
- D
$2556$
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In how many ways a team of $10$ players out of $22$ players can be made if $6$ particular players are always to be included and $4$ particular players are always excluded
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All possible numbers are formed using the digits $1, 1, 2, 2, 2, 2, 3, 4, 4$ taken all at a time. The number of such numbers in which the odd digits occupy even places is
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- [JEE MAIN 2019]
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If $^{20}{C_{n + 2}}{ = ^n}{C_{16}}$, then the value of $n$ is
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