If $\left| {\,\begin{array}{*{20}{c}}{x + 1}&3&5\\2&{x + 2}&5\\2&3&{x + 4}\end{array}\,} \right| = 0$, then $ x =$

  • A

    $1, 9$

  • B

    $-1, 9$

  • C

    $-1, -9$

  • D

    $1, -9$

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