3 and 4 .Determinants and Matrices
easy

જો $A = \left[ {\begin{array}{*{20}{c}}0&1&{ - 2}\\{ - 1}&0&5\\2&{ - 5}&0\end{array}} \right]$, તો

A

$A' = A$

B

$A' = - A$

C

$A' = 2A$

D

એકપણ નહી.

Solution

(b) $A' = \left[ {\begin{array}{*{20}{c}}0&{ – 1}&2\\1&0&{ – 5}\\{ – 2}&5&0\end{array}} \right] = – A$.

Standard 12
Mathematics

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