3 and 4 .Determinants and Matrices
easy

If $A = [a\,\,b],B = [ - b - a]$ and $C = \left[ \begin{array}{l}\,\,\,\,a\\ - a\end{array} \right]$, then the correct statement is

A

$A = - B$

B

$A + B = A - B$

C

$AC = BC$

D

$CA = CB$

Solution

(c) $AC = [a\,\,\,b]\,\,\left[ \begin{array}{l}\,\,\,a\\ – a\end{array} \right] = [{a^2} – ab]$

$BC = [ – b\,\,\, – a]\,\left[ \begin{array}{l}\,\,\,a\\ – a\end{array} \right] = [{a^2} – ab]$

$\therefore$ $AC = BC$.

Standard 12
Mathematics

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