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3 and 4 .Determinants and Matrices
normal
If $A = \left[ \begin{array}{l}1\\2\\3\end{array} \right],$then $AA' = $
A
$[14]$
B
$\left[ \begin{array}{l}1\\4\\3\end{array} \right]$
C
$\left[ {\begin{array}{*{20}{c}}1&2&3\\2&4&6\\3&6&9\end{array}} \right]$
D
None of these
Solution
(c)$A' = [1\,\,2\,\,3]$ therefore $AA' = \left[ \begin{array}{l}1\\2\\3\end{array} \right]\,\,[1\,\,2\,\,3] = \left[ {\begin{array}{*{20}{c}}1&2&3\\2&4&6\\3&6&9\end{array}} \right]$.
Standard 12
Mathematics