If 3({sec ^2}theta + {tan ^2}theta ) = 5, the | vedclass

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(c) ${\sec ^2}	heta + {	an ^2}	heta = \frac{5}{3}$, 

also ${\sec ^2}	heta - {	an ^2}	heta = 1$

$ \Rightarrow $ ${	an ^2}	heta = \fr

Vedclass · Accepted Answer

$n\pi \pm \frac{\pi }{6}$

Vedclass · Answer

(c) ${\sec ^2}	heta + {	an ^2}	heta = \frac{5}{3}$, 

also ${\sec ^2}	heta - {	an ^2}	heta = 1$

$ \Rightarrow $ ${	an ^2}	heta = \frac{1}{3} = {	an ^2}\left( {\frac{\pi }{6}} ight) $

$\Rightarrow 	heta = n\pi \pm \frac{\pi }{6}$.

If $3({\sec ^2}\theta + {\tan ^2}\theta ) = 5$, then the general value of $\theta $ is

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