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Trigonometrical Equations
easy
જો $r\,\sin \theta = 3,r = 4(1 + \sin \theta ),\,\,0 \le \theta \le 2\pi ,$ તો $\theta = $
A
$\frac{\pi }{6},\frac{\pi }{3}$
B
$\frac{\pi }{6},\frac{{5\pi }}{6}$
C
$\frac{\pi }{3},\frac{\pi }{4}$
D
$\frac{\pi }{2},\pi $
Solution
(b) Eliminating $r$, we get
$\because$ $\sin \theta = \frac{1}{2},\, – \frac{3}{2}$ (rejected)
$ \Rightarrow $ $\theta = \frac{\pi }{6},\,\pi – \frac{\pi }{6} = \frac{{5\pi }}{6}$.
Standard 11
Mathematics
