If tan (cot x) = cot (tan x), then sin 2x = | vedclass

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Question

(b)$	an (\cot x) = \cot (	an x)$

$ \Rightarrow $ $	an (\cot x) = 	an \left( {\frac{\pi }{2} - 	an x} ight)$ 

$ \Rightarrow $ $\

Vedclass · Accepted Answer

$\frac{4}{{(2n + 1)\pi }}$

Vedclass · Answer

(b)$	an (\cot x) = \cot (	an x)$

$ \Rightarrow $ $	an (\cot x) = 	an \left( {\frac{\pi }{2} - 	an x} ight)$ 

$ \Rightarrow $ $\cot x = n\pi  + \frac{\pi }{2} - 	an x $

$\Rightarrow \cot x + 	an x = n\pi  + \frac{\pi }{2}$

$ \Rightarrow $ $\frac{2}{{\sin 2x}} = n\pi  + \frac{\pi }{2}$

$\Rightarrow \sin 2x = \frac{2}{{n\pi  + \frac{\pi }{2}}} = \frac{4}{{(2n + 1)\pi }}$

If $\tan (\cot x) = \cot (\tan x),$ then $\sin 2x =$

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