Gujarati
10-1.Circle and System of Circles
easy

If $2x - 4y = 9$ and $6x - 12y + 7 = 0$ are the tangents of same circle, then its radius will be

A

$\frac{{\sqrt 3 }}{5}$

B

$\frac{{17}}{{6\sqrt 5 }}$

C

$\frac{{2\sqrt 5 }}{3}$

D

$\frac{{17}}{{3\sqrt 5 }}$

Solution

(b) Since the tangents are parallel, therefore the distance between these two tangents will be its diameter

$i.e$., diameter $ = \frac{{34}}{{\sqrt {180} }}$

$= \frac{{17}}{{3\sqrt 5 }}$

Hence, radius $ = \frac{{17}}{{6\sqrt 5 }}$.

Standard 11
Mathematics

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