- Home
- Standard 11
- Mathematics
10-1.Circle and System of Circles
easy
The normal to the circle ${x^2} + {y^2} - 3x - 6y - 10 = 0$at the point $(-3, 4)$, is
A
$2x + 9y - 30 = 0$
B
$9x - 2y + 35 = 0$
C
$2x - 9y + 30 = 0$
D
$2x - 9y - 30 = 0$
Solution
(a) $\frac{{x – {x_1}}}{{{x_1} + g}} = \frac{{y – {y_1}}}{{{y_1} + f}}$
$ \Rightarrow \frac{{x + 3}}{{ – 3 – \frac{3}{2}}} = \frac{{y – 4}}{{4 – 3}} $
$\Rightarrow 2x + 9y – 30 = 0$.
Standard 11
Mathematics