Gujarati
10-1.Circle and System of Circles
easy

The normal to the circle ${x^2} + {y^2} - 3x - 6y - 10 = 0$at the point $(-3, 4)$, is

A

$2x + 9y - 30 = 0$

B

$9x - 2y + 35 = 0$

C

$2x - 9y + 30 = 0$

D

$2x - 9y - 30 = 0$

Solution

(a) $\frac{{x – {x_1}}}{{{x_1} + g}} = \frac{{y – {y_1}}}{{{y_1} + f}}$

$ \Rightarrow \frac{{x + 3}}{{ – 3 – \frac{3}{2}}} = \frac{{y – 4}}{{4 – 3}} $

$\Rightarrow 2x + 9y – 30 = 0$.

Standard 11
Mathematics

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