If $P \equiv (x,\;y)$, ${F_1} \equiv (3,\;0)$, ${F_2} \equiv ( - 3,\;0)$ and $16{x^2} + 25{y^2} = 400$, then $P{F_1} + P{F_2}$ equals

  • [IIT 1998]
  • A

    $8$

  • B

    $6$

  • C

    $10$

  • D

    $12$

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